Question

How many moles of kno3 are required to make 0.50 liters of a 2.0 m solution of kno3?

Answer 1

1.0 moles of
`KNO_3` are required to make 0.50 liters of a 2.0 m solution of
`KNO_3`.

Step-by-step explanation:

`Molarity(M)=(Moles(n))/(Volume(L))`

`Moles (n)=Molarity(M)* Volume (L)`

Moles of potassium nitrate = n

Volume of potassium nitrate solution = 0.50 L

Molarity of the potassium nitrate = 2.0 M

`n=2.0 M* 0.50 L=1.0 mol`

1.0 moles of
`KNO_3` are required to make 0.50 liters of a 2.0 m solution of
`KNO_3`.

Answer 2

Molarity is defined as the number of moles of solute dissolved in 1 L of solution.
KNO₃ - 2.0 M this means that 2.0 moles of KNO₃ are in 1 L of solution.
If 1 L contains - 2.0 moles
then 0.50 L contains - 2 mol/L x 0.50 L = 1 mol
Therefore 1 mol of KNO₃ is in 0.50 L solution.