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Find the 76th term of the arithmetic sequences 16 14 12

User GMichael
by
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1 Answer

2 votes

Answer:

a₇₆ = - 134

Explanation:

The n th term of an arithmetic sequence is


a_(n) = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 16 and d = a₂ - a₁ = 14 - 16 = - 2, then

a₇₆ = 16 + (75 × - 2) = 16 - 150 = - 134

User Chris Maurer
by
8.7k points

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