Question

How do you solve this question?

Answer 1

We can use the quadratic formula to solve this problem.


`\sf x=(-b\pm√(b^2-4ac))/(2a)`

You've already listed the values for 'a', 'b', and 'c', so just plug them into the formula:


`\sf x=(-(-12)\pm√((-12)^2-4(4)(9)))/(2(4))`

Simplify:


`\sf x=(12\pm√(144-4(4)(9)))/(8)`

Multiply:


`\sf x=(12\pm√(144-144))/(8)`

Subtract:


`\sf x=(12\pm√(0))/(8)`

Take the square root:


`\sf x=(12\pm 0)/(8)`

It doesn't matter if you add or subtract something with 0, you'll end up with the same thing, so we have:


`\sf x=(12)/(8)\rightarrow\boxed{\sf 1(1)/(2)}`