X^4-28x^2=0 solve algebraically

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Guilffer · Answer 1 · 2019-10-29T11:43:54+0000

$x^2 = 0 \ \ or \ \ (x^2 - 28) = 0$

$x = 0 \ \ or \ \ x^2 = 28$

$x = 0 \ \ or \ \ x = \pm √(28)$

$x = 0 \ \ or \ \ x = \pm2 √(7)$

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Answer : x = 0 or 2√7 or -2√7
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X^4-28x^2=0 solve algebraically

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