Question

Find the values for a and b that would make the equality true.

–3(2x2 + ax +b) = -6x2 + 12x – 15
a =
b=

Answer 1

a = - 4, b = 5

Explanation:

Expand the left side, then compare the coefficients of like terms.

- 3(2x² + ax + b)

= - 6x² - 3ax - 3b, compare to - 6x² + 12x - 15

Compare coefficients of x- terms

- 3a = 12 ( divide both sides by - 3 )

a = - 4

Compare constant terms

- 3b = - 15 ( divide both sides by - 3 )

b = 5