Question

Nadine walked 1⁄4 of a mile, Janet walked 3⁄8 of a mile, and Perry walked 5⁄6 of a mile. Who walked the farthest? How much farther did Perry walk than Nadine?

Answer 1

Perry walked the farthest

Nadine = 6/24
Janet = 9/24
Perry = 20/24

Perry walked 7/12 miles more than Nadine.

Hope this helps.

Answer 2

Perry walked the farthest.

Perry walked
`(7)/(12)` of a mile farther than Nadine.

Explanation:

We have been given that Nadine walked 1⁄4 of a mile, Janet walked 3⁄8 of a mile, and Perry walked 5⁄6 of a mile.

To find who walked the farthest, we will compare our given fraction by making a common denominator.

`(1)/(4).(3)/(8),(5)/(6)`

We know that 24 is the least common multiple of 4, 6 and 8, so we can have a common denominator as:

`(1*6)/(4*6).(3*3)/(8*3),(5*4)/(6*4)`

`(6)/(24).(9)/(24),(20)/(24)`

Since
`(20)/(24)` in the greatest of the given fractions, therefore, Perry walked the farthest.

To find the difference between distance walked by Perry and Nadine, we will subtract
`(1)/(4)` from
`(5)/(6)`.

`(5)/(6)-(1)/(4)`

`(5*2)/(6*2)-(1*3)/(4*3)`

`(10)/(12)-(3)/(12)`

`(10-3)/(12)=(7)/(12)`

Therefore, Perry walked
`(7)/(12)` of a mile farther than Nadine.