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Triangle ABC has the given measures. Solve the triangle(s), if any exist.

A = 162°, a = 6.1, b = 4

How many triangle(s) can possibly be formed?

2 Answers

7 votes

Answer:

1

12

6

2

Explanation:

on edge

User Anthony DeRosa
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7.1k points
4 votes
Since A>90° and a>b, we can only form one triangle.
Lest solve it:
First we are going to use the law of sine to find the angle B:

(SinB)/(b) = (SinA)/(a)

(SinB)/(4) = (Sin(162))/(6.1)

SinB= (4Sin(162))/(6.1)

B=arcSin((4Sin(162))/(6.1))

B=11.7°

To find angle C, we are going to take advantage of the fact that the sum of the interior angels of a triangle is 180°:

C=180-(162+11.7)

C=180-173.7

C=6.3

To find the remaining side c, we are going to use the law of sines:

(c)/(SinC) = (a)/(SinA)

(c)/(Sin(6.3)) = (6.1)/(Sin(162))

c= (6.1Sin(162))/(Sin(6.3))

c=3.6

We can conclude that we can only form a triangle with the given measures.
Triangle ABC has the given measures. Solve the triangle(s), if any exist. A = 162°, a-example-1
User Object
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7.4k points