Question

Find the acceleration of a body whose velocity increases from 11ms-1 to 33ms-1 in 10 seconds

Answer 1

as we know that
a= dell V/t
then put values
a= 2ms/^2

Answer 2

Acceleration is equivalent to the rate of change of velocity.

Calculate the difference of velocity, and divide by the total time it took for the change to happen.


`(33 (m)/(s) - 11 (m)/(s) ) / 10seconds \\ = 2 \frac{m}{ {s}^(2) }`
That is the answer.