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Al dividir (x^2-9/x^2+2x-3) / (x^2+6x-27/x^2-10x+9) se obtiene: A x/x+9 B x-9/x+9 C x+9/x-9 D 9/x-9

2 Answers

3 votes

Answer:

B x-9 / x + 9

Explanation:

User Ninaj
by
8.5k points
5 votes
We have the following expression:
(x ^ 2-9 / x ^ 2 + 2x-3) / (x ^ 2 + 6x-27 / x ^ 2-10x + 9)
Let's rewrite the expression:
(((x-3) * (x + 3)) / ((x + 3) * (x-1))) / (((x + 9) * (x-3)) / ((x-9) ) * (x-1)))
We cancel similar terms:
(1/1) / ((x + 9) / (x-9))
Doing double c we have:
(x-9) / (x + 9)
Answer:
B x-9 / x + 9
User Euthyphro
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8.3k points