Question

Simplify 1/6+5i to get a complex number in standard a +bi form

Answer 1

1/6+5i =(1/6+5i)*(6-5i/6-5i)

1/6+5i = (6-51/36-30i+30i-25i²)1/6+5i = (6-5i/36+25)

1/6+5i = (6-5i/61)

1/6+5i = 6/61-(5/61)*i

Answer 2

Multiply numerator and denominator by the complex conjugate.

1/6+5i =(1/6+5i)*(6-5i/6-5i)
1/6+5i = (6-51/36-30i+30i-25i²)1/6+5i = (6-5i/36+25)
1/6+5i = (6-5i/61)
1/6+5i = 6/61-(5/61)*i