The average value of cosx on the interval [-3, 5] is

Question

asked Dec 6, 2019 193k views

1 Answer

Magiczne · Answer 1 · 2019-12-09T16:23:37+0000

Answer:

\frac{1}{8} (sin 5+sin 3)

Explanation:

step 1:-

average value of given function =
$(1)/(b-a) \int\limits^a_b {f(x)} \, dx$

[
$(1)/(8)(sin 5-(sin(-3)) \\\\(1)/(8) (sin 5+sin 3)$

Final answer:-

\frac{1}{8} (sin 5+sin 3)