Question

The length of a rectangle is 5ft longer than twice the width if the perimeter is 58 ft find the length and width of the rectangle

Answer 1

Length= 5+2x
Width = x

Perimeter = 2(l+w)=58
= 2(5+2x+x)=58
= 2(5+3x)=58
= 10+6x =58
= 6x= 48
X= 8
Width=8
Length= 21

Answer 2

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Define x :
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Let the width be x.
Width = x
Length = 2x + 5 // Length is 5ft longer than twice the width

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Formula for Perimeter :
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Perimeter = 2 (Length + Width)

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Find Width :
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58 = 2 ( 2x + 5 + x) // Substitute Length and Width into formula
58 = 2 (3x + 5) // Combine like terms
58 = 6x + 10 // Apply distributive property
48 = 6x // Take away 10 from both sides
6x = 48 // Switch sides. Make x the subject
x = 8 // Divide by 6 on both sides

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Find Length and Width :
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Width = x = 8 ft
Length = 2x + 5 = 2(8) + 5 = 21 ft

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Answer: The length is 21 ft and the width is 8 ft.
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