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If 3.50 L of propane at 24°C and 62.2 kPa is completely burned in excess oxygen, how many moles of carbon dioxide will be produced?
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If 3.50 L of propane at 24°C and 62.2 kPa is completely burned in excess oxygen, how many moles of carbon dioxide will be produced?

User AMoL Thite
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1 Answer

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1) convert Celsius to Kelvin
24 + 273 = 297

2) convert kPa to atm
62.2 / 101.3 = 0.614

3) plug numbers into the ideal gas law formula

Answer: 0.088 mols
If 3.50 L of propane at 24°C and 62.2 kPa is completely burned in excess oxygen, how-example-1
User Nilesh
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