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The force acting between two charged particles A and B is 5.2 * 10È¢ newtons. Charges A and B are 2.4 * 10ÈÆ meters apart. If the charge on particle A is 7.2 * 10ȧ coulombs, what is the charge of particle B? (k = 9.0 * 10© newton·metersÆ/coulombÆ)

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5 votes
The correct question is shown in the image attached with.

This is a question of Physics. Concept of Coulomb Force is used here. The formula for the Coulomb Force is:


F=k ( q_(1) q_(2) )/( r^(2) )

F, k, r and
q_(1) are known and we are to find
q_(2) . Using the given values, we can write:


5.2* 10^(-5)=9*10^(9)* (7.2*10^(-8)* q_(2) )/((2,4 x 10^(-2) )^(2) )

Simplifying and solving the equation for
q_(2) we get:

The charge of particle B =
q_(2)=4.6*10^(-11) Coulomb.

The force acting between two charged particles A and B is 5.2 * 10È¢ newtons. Charges-example-1
User Amos Batto
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