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Q is equidistant from the sides of TSR. Find the value of x. The diagram is not to scale.

A. 3
B. 23
C. 20
D. 11

Q is equidistant from the sides of TSR. Find the value of x. The diagram is not to-example-1

2 Answers

1 vote


2x + 17 = 23

2x = 6

x = 3

The answer is A! Hope this helps! :)
User Jim Biancolo
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8.1k points
5 votes
ANSWER


x = 3

Step-by-step explanation

Since the ray through Q is equidistant from, TSR, it bisects angle TSR.

This implies that, the
23\degree angle is equal to the
(2x + 17) \degree angle. We therefore write the following equation that can help us find the value of x.


(2x + 17) \degree=23 \degree

We group like terms to get,


2x=23\degree- 17\degree

This gives us,


2x=6

We divide both sides by 3 to get,


x=(6)/(2)


\therefore\:x=3

The correct answer is A.
User Kaleb Portilho
by
7.8k points