Question

What are the coordinates of the vertex of the function below?write your answer in the form (x,y).

y+9=-6(x-2)^2

Answer 1

The equation in standard form is y - k = a(x - h)², so the vertex takes the place of (h, k), and we get (2, -9).
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Hope this helps!

Answer 2

vertex is (2,-9)

Explanation:

`y+9=-6(x-2)^2`

The general vertex form of quadratic equation is

`y=a(x-h)^2+k`

Where (h,k) is the vertex

First we solve the given equation for y. then compare the given equation with the general equation.

`y+9=-6(x-2)^2`

Subtract 9 from both sides

`y=-6(x-2)^2-9`

The value of h=2 and the value of k = -9

So vertex is (2,-9)