Question

The equilibrium constant for the reaction of carbon monoxide with water is 1.845. if 1.00 mol of each reactant is placed in a 2.00 l container, what is the concentration of carbon dioxide at equilibrium? co(g) + h2o(g) co2(g) + h2(g)

Answer 1

Answer: 0.288 M

Step-by-step explanation:

Answer 2

[CO] = 1 mol / 2L = 0.5 M

[
According to the equation:

and by using the ICE table:

CO(g) + H2O(g) ↔ CO2(g) + H2(g)

initial 0.5 0.5 0 0

change -X -X +X +X

Equ (0.5-X) (0.5-X) X X

when Kc = X^2 * (0.5-X)^2

by substitution:

1.845 = X^2 * (0.5-X)^2 by solving for X

∴X = 0.26

∴ [CO2] = X = 0.26