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Use theorem 7.1.1 to find {f(t)}. (write your answer as a function of s.) f(t) = t2 + 5t − 6 {f(t)} =

User Halcwb
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2 Answers

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f(s) = (2s)/(s^3) + 5/(s^2) - 6/s
User Oleg Gopkolov
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1 vote

General Idea:

Let
f be a function defined for
t\geq 0. Then the integral


L\{f(t)\}=\int\limits^\infty_0 {e^(-st)f(t)} \, dt

is said to be Laplace transform of
f, provided that the integral converges.


L\{1\}=(1)/(s) \\ \\ L\{t^n\}=(n!)/(s^(n+1)) , \; \; \; n=1,\;2, \;3,...

Applying the concept:


L\{f(t)\}=L\{t^2\}+L\{5t\}-L\{6\}=(2)/(s^3) +(5)/(s^2) -(6)/(s)

User Vitorbal
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