Question

Calculate the concentration of so42− ions in a 0.010 m aqueous solution of sulfuric acid. express your answer to four decimal places and include the appropriate units.

Answer 1

The concentration of SO4²⁻ ions in a 0.010 M sulfuric acid solution is 0.0100 M because sulfuric acid fully dissociates in water, releasing one sulfate ion for each molecule of acid.

Step-by-step explanation:

To calculate the concentration of SO4²⁻ ions in a 0.010 M aqueous solution of sulfuric acid (H2SO4), it is important to understand the dissociation process of sulfuric acid in water. Sulfuric acid is a strong acid and fully dissociates in water to form hydrogen ions (H⁺) and sulfate ions (SO4²⁻). The dissociation equation is as follows: H2SO4(aq) -> 2H⁺(aq) + SO4²⁻(aq). Since each molecule of sulfuric acid releases one sulfate ion, the concentration of sulfate ions will be equal to the initial concentration of the sulfuric acid.

Therefore, the concentration of SO4²⁻ ions in a 0.010 M solution of sulfuric acid is 0.0100 M.

Answer 2

The concentration of sulfate ions is 0.0100 M.

Step-by-step explanation:

Concentration of sulfuric acid =0.0100 M

`H_2SO_4\rightarrow 2H^++SO_4^(2-)`

1 mol of sulfuric acid gives 2 mole of
`H^+` ion and 1mole of
`SO_4^(2-)`ion.

`[SO_4^(2-)]=1* 0.010 M=0.0100 M`

`[H^+]=2* 0.010 M=0.0200 m`

The concentration of sulfate ions is 0.0100 M.