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Dennis Gorelik · Answer 1 · 2019-06-14T14:53:57+0000

The volume of the gas is
$V=0.923 L=0.923 \cdot 10^(-3) m^3$
The temperature of the gas is
$T=25^(\circ)C + 273 = 298 K$

Charle's law can be written as:

(V)/(T) =k

So, by using the values of V and T, we can find the value of k, the Charle's law constant:

$k=(0.923 \cdot 10^(-3) m^3)/(298 K)=3.10 \cdot 10^(-6) m^3 K^(-1)$

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