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Divide (3x^3+5x) by (x+3)

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Using synthetic division:

Draw an upside down division symbol. Place the constant of x + 3 (-3) on the outside, and the coefficients of 3x³ + 5x on the inside, like so:

| x³ x² x¹ x⁰
-3 | 3 0 5 0
|
|___________

Bring down the first coefficient:

| x³ x² x¹ x⁰
-3 | 3 0 5 0
|
|___________
3

Multiply the number outside the symbol (-3) by the 3 you've just brought down. Place that number under the next coefficient to the right.

| x³ x² x¹ x⁰
-3 | 3 0 5 0
| -9
|___________
3

Add the new number (-9) to the coefficient above it and place that number directly underneath it.

| x³ x² x¹ x⁰
-3 | 3 0 5 0
| -9
|___________
3 -9

Repeat this process until you've reach the end of the symbol.

| x³ x² x¹ x⁰
-3 | 3 0 5 0
| -9 27 -96
|___________
3 -9 32 -96

The resulting numbers are coefficients, the first three of the quotient, and the last one of the remainder. The remainder is the last coefficient (-96) over the divisor.

(3x^3+5x) / (x+3) = 3² - 9x + 32 + -96 / x + 3
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