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If the endpoints of the diameter of a circle are (-14, 4) and (-2, 0) what is the standard form equation of the circle

User Lukie
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2 Answers

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Do the distance formula first! The distance formula is d=√(x2-x1)^2+(y2-y1)^2. For this, you would do d= √(-2- -14)^2 + (0-4)^2. You would get √(12)^2 + (-4)^2. The answers to those would be √144 + 16, doing an eventual √160. √16 and √10 go into √160. The final answer is 4√10.
User Raunak Thomas
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4 votes

(x + 8)2 + (y − 2)2 = 40
User Pavel Alekseev
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