For all three of these expressions, we need to plug in the given numbers for x. We can begin with the first expression:
f(x) = 2x - 5
We need to plug in 3 first:
f(x) = 2(3) - 5
f(x) = 6 - 5
f(x) = 1
Now let’s solve the second one, where we will plug 0 in:
h(x) = 6x + 2
h(x) = 6(0) + 2
h(x) = 0 + 2
h(x) = 2
The third question cuts off so I cannot accurately answer it.
Answer Recap: Question 10: f(x) = 1
Question 11: h(x) = 2