Question

A rubber band has potential energy of 5 J. If the spring constant of the rubber band is 50 N/m, what is the displacement of the rubber band?

0.2 m
1.2 m
0.4 m
0.8 m

Answer 1

The answer is C. 0.4m

Answer 2

Step-by-step explanation:

The elastic potential energy stored in a sprig is given by

`U = (1)/(2)Kx^(2)`

Where, K is the spring constant and x be the displacement.

Substitute, K = 50 N/m and U = 5 J

`5 = (1)/(2)* 50* x^(2)`

By solving, we get

x = 0.44 m = 0.4 m0.4 m