Answer:
The correct answer is option C.
Explanation:
Simple interest
S.I =

P = Principal amount
R = Rate
T = Time period
We have:
P = $250
R = 3%
Amount present at beginning of year 14 means that amount made in 13 years of time period = A
T = 13 years


A = $347.50
The general formula of the given situation will be:

The amount in beginning of year 14 wil be $347.50.