Solution:
As, you must keep in mind , if you draw perpendicular bisector of chords of a circle they will intersect at the center.
So, in triangle BCD, BC, CD and BD are chords of circle. Perpendicular bisector of BC, CD and BD will intersect at the center O.
Similarly, in triangle BED, BE,ED and BD are chords of circle. when you will draw perpendicular bisector of all these chords they will meet each other at point O.
Option : C The perpendicular bisectors of BCD intersect at the same point as those of BED.