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The area of triangle ABC is _____.

A.
60 u^2
B.
65 u^2
C.
130 u^2
D.
150 u^2

User Ariana
by
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1 Answer

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I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
SEE ATTACHED IMAGE.
Using Heron's Formula we can find the area of the triangle.
A = root (s (s-a) * (s-b) * (s-c))
s = (a + b + c) / 2
Where,
s: semi-perimeter
a, b, c: sides of the triangle
Substituting values:
s = (15 + 16 + 20) / 2
s = 25.5
s = 26
The area will be:
A = root (26 * (26-15) * (26-16) * (26-20))
A = 130.9961832
A = 130 u ^ 2
Answer:
The area of triangle ABC is:
C.
130 u ^ 2
The area of triangle ABC is _____. A. 60 u^2 B. 65 u^2 C. 130 u^2 D. 150 u^2-example-1
The area of triangle ABC is _____. A. 60 u^2 B. 65 u^2 C. 130 u^2 D. 150 u^2-example-2
User Praveen D
by
6.2k points