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−8x+44≥60 AND−4x+50<58

User Scherrie
by
7.9k points

2 Answers

1 vote

Answer:

The set of inequalities have no solution.

Explanation:

We are given two inequalities:


-8x+44\geq 60 \\-4x+50<58

Solving the two inequalities, we have:


-8x+44\geq 60\\-8x+44-44\geq 60-44\\-8x \geq 16\\\displaystyle(-8x)/(-8) \leq (16)/(-8)\\\\x \leq -2\\\text{In interval notation, we can write,}\\x \in (-\infty, -2]


-4x+50<58\\-4x +50-50 < 58-50\\-4x < 8\\\displaystyle(-4x)/(-4) > (8)/(-4)\\\\x > -2\\\text{In interval notion we can write,}\\x \in (-2, \infty)

For the solution of both the inequalities, we have


x \in (-\infty,-2] \cap (-2,\infty) = \phi

Thus,the set of inequalities have no common solution, hence, no solution.

User Pshoukry
by
8.2k points
4 votes

Answer:

No Solution

Explanation:


-8x+44\geq 60 and &nbsp;-4x+50<58

WE solve each inequality separately then we combine the answers


-8x+44\geq 60

Subtract 44 from both sides


-8x\geq 16

Divide by
-8 on both sides , when we divide by negatie number then we flip the inequality sign


x \leq -2

now solve the other inequality


-4x+50<58

Subtract 50 on both sides


-4x<8

Divide by
-4


x > -2

Consider both inequlities


x \leq -2 and
x > -2

There is no intersection between both inequalities

So no solution

User Majid
by
9.0k points

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