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7. If the area of the outer square is 4x², then the area of the inner square is (a) x²/2 (b) x² (c) √2x² (d) 2x² (e) 2√2x²
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30 votes
30 votes
7. If the area of the outer square is 4x², then the area of the inner square is

(a) x²/2
(b) x²
(c) √2x²
(d) 2x²
(e) 2√2x²

User Renis
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1 Answer

17 votes
17 votes
Area of Outer Square = 4x^2 so side will be 2x and 2x is diameter of inner circle and that is also diagonal of of inner square.
As per formula A=d^2/2 and we know that d = 2x so (2x)^2/2 that is 2x^2
Answer is D
User Gxyd
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