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One of the roots of the equation x2−13x+q=0 is 12.5. Find the other root and the value of the coefficient q.

1 Answer

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Let's factor the following polynomial to find the roots:
x2-13x + q = 0
Factoring we have:
(x-12.5) * (x + a)
Where,
-12.5 + a = -13
a = -13 + 12.5
a = -0.5
We now look for the coefficient q:
q = -12.5 * a
q = -12.5 * (- 0.5)
q = 6.25
The polynomial will then be:
x2-13x + 6.25 = 0
Its roots are:
x1 = 12.5
x2 = 0.5
Answer:
The other root and the value of the coefficient are:
0.5 and 6.25 (Respectively)
User Pedro Lopes
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