Question

A negative charge of -2.0 C and a positive charge of 3.0 C are separated by 80 m. What is the force between the two charges?

Answer 1

The force between two charges can be calculated using Coulomb's Law. In this case, the force between a negative charge of -2.0 C and a positive charge of 3.0 C separated by 80 m is approximately -2.53125 N.

Step-by-step explanation:

The force between two charges can be calculated using Coulomb's Law, which states that the force between two charges is proportional to the product of their magnitudes and inversely proportional to the square of the distance between them. Mathematically, it can be expressed as:

F = k * (q1 * q2) / r^2

Where F is the force, q1 and q2 are the magnitudes of the charges, r is the distance between them, and k is the electrostatic constant, which is equal to 8.99 * 10^9 Nm^2/C^2.

In this case, we have a negative charge of -2.0 C and a positive charge of 3.0 C separated by a distance of 80 m. Plugging these values into the formula, we get:

F = (8.99 * 10^9 Nm^2/C^2) * (-2.0 C * 3.0 C) / (80 m)^2

Simplifying the expression, the force between the two charges is approximately -2.53125 N (negative because the charges have opposite signs).

Answer 2

The force between two charged particles is an electrostatic force. The intensity of this force is given by the following formula:

`F_c=k_c(q_1q_2)/(r^2)`
Where q1 and q2 are charges r is the distance, and k_c is Coulomb's constant.
Coulomb's constant has the value of:

`k_c=8.9875\cdot 10^9(Nm^2)/(C^2)`
When we plug all the given values into the formula we get:

`F_c=8.9875\cdot 10^9\cdot(-2\cdot3)/(80^2)=-8425781 $N`
Negative sign means that force is attractive.