a) Since we know they have equal perimeters, we can set them equal to each other. First, let's recap the perimeters of squares and triangles (s = side):

Now, we can set up our equation:


We can solve for x:



So,
x = 10.
b) We known the perimeter formulas and we have what x is. So, let's just plug and chug.
Square:

So, the perimeter of the square is
28 unitsĀ².
Since their perimeters are equal the perimeter of the triangle is also
28 unitsĀ²