Answer:
ED is a midsegment of CAB.
Explanation:
Given
D is the midpoint of segment AB
Therefore,DB=DA
E is the midpoint of segment BC
Therefore, BE=EC
F is the midpoint of AC
Therefore, CF=FA
Mid segment theorem: In a triangle , the segment joining midpoints of any two sides will be parallel to the third side and half of its length.The segment joining midpoints of two sides is called mid segment.
The segment ED is the only segment in the given figure which join the midpoint of two sides BC and AB.
By midsegment theorem
Hence,segment ED is a mid segment of CAB.