What is the change in temperature after 840 Joules is absorbed by 10.0g of water is heated?(Specific heat of water is 4.184 J/g °C)

John Carrell asked Sep 28, 2023

307,079 views

12 votes

John Carrell asked Sep 28, 2023

3.2k points

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

17 votes

Answer:

dt=20.08

Step-by-step explanation:

Q=msdt

840=10*4.184*dt

dt=840/(10*4.184)

dt=20.08

Anber answered Oct 4, 2023

by Anber

2.4k points

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers