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A box contains five slips of paper, each with one of the letters A, B, C, D, or E written on it. Another box has four slips of paper, each with one of the numbers 1, 2, 3, or 4 written on it. Without looking, Nancy draws a slip of paper from each box. What is the probability that Nancy draws the letter B from one box and the number 2 from the other box?

User SuperCop
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20% chance for the letter box and 25% chance for Number box.

User NITEMAN
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5 votes

Answer:

The probability that Nancy draws the letter B from one box and the number 2 from the other box is:


(1)/(20)

Explanation:

We know that the probability of drawing a slip of paper from one box is independent of drawing a piece of slip from the other.

Let first box contain five slips of paper, each with one of the letters A, B, C, D, or E written on it.

This means that the probability of drawing B is:

ratio of the number of slips containing B to the total number of slips.

i.e.


P(Drawing\ B)=(1)/(5)

Second box has four slips of paper, each with one of the numbers 1, 2, 3, or 4 written on it.

This means that the probability of drawing number 2 is:

ratio of the number of slips containing number 2 to the total number of slips.

i.e.


P(Drawing\ 2)=(1)/(4)

Hence,


P(drawing\ B\ and\ number\ 2)=P(drawing\ B)* P(drawing\ 2)\\\\i.e.\\P(drawing\ B\ and\ number\ 2)=(1)/(5)* (1)/(4)\\\\P(drawing\ B\ and\ number\ 2)=(1)/(20)

Hence, the probability is:


(1)/(20)

User RmIu
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