Question

A 1.00 L volume of HCl reacted completely with 2.00 L of 1.50 M Ca(OH)2 according to the balanced chemical equation below. 2HCl + Ca(OH)2 mc013-1.jpg CaCl2 + 2H2O What was the molarity of the HCl solution? 0.375 M 1.50 M 3.00 M 6.00 M

Answer 1

The answer is D
6.00 M. I just took the test

Answer 2

The molarity of the HCl solution is 6.00M

Calculation

2HCl + Ca(OH)2→ CaCl2 +2H2O

Step 1:find the moles of Ca(OH)2

= molarity x volume

= 2l x 1.5 mol/l = 3 .00 moles

Step 2:use the mole ratio of HCl : Ca(OH)2 to calculate the moles of HCl

That is Ca(OH)2 :HCl is 2:1 therefore the moles of HCl= 3.00 moles x2= 6.00 moles.

step 3: find the molarity of HCl

molarity of HCl = moles of HCL / volume in liters of HCl

= 6.00 moles/ 1 L = 6.00 M