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Find the distance between (-2,4) & (5, 1) on the CCS. Please explain how you did it please.
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1 vote
Find the distance between (-2,4) & (5, 1) on the CCS. Please explain how you did it please.

User Andrew McKee
by
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1 Answer

3 votes
A(x1, y1), B (x2,y2)

d=V(y2-y1)^2+(x2-x1)^2

d^2= (1-4)^2+[5-(-2)]^2=(-3)^2+ (5+2)^2=9+49=58

d=V58
User Ventiseis
by
8.0k points
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