Question

How much heat is released when 25.0 grams of liquid copper at its freezing point of 1,085°C changes to solid? The latent heat of fusion of copper is 205.0 J/g.

Answer 1

–5,130 J

Step-by-step explanation

answer right on edge

Answer 2

Answer : Heat release, Q = -5125 J

Explanation :

It is given that,

Mass of liquid copper, m = 25 grams

The heat of fusion of copper, L = 205 J/g

The latent heat of fusion is defined as the amount of heat required to convert solid into liquid phase for one gram of substance.

But in this case, it is required to find the amount of heat released when liquid copper changes to solid.

So, L = - 205 J/g

To find the amount of heat released when 25.0 grams of liquid copper at its freezing point of 1,085°C changes to solid, we can use unitary method.

So,
`Q=-205\ \J/g* 25\ g`

Q = -5125 J

Hence, this is the required solution.