Question

A block is released from rest on an inclined plane and moves 3 m during the next 4.1 s. The acceleration of gravity is 9.8 m/s 2 .

Answer 1

Answer: angle = 2°

Step-by-step explanation:

Let the angle of inclination be θ,

as shown in figure the forces equation on the block are as follows

Fsinθ = ma , where F=mg

mgsinθ = ma

sinθ =
`(a)/(g)`....................eq1

now we know that s = ut + 1/2at*t

3 = 0+1/2at*t

6 = a*[16.81]

a = 0.357m/s*s

now put value of a in eq1

therefore sinθ = 0.357/9.8=0.0364

angle θ = 2°