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What is the perimeter of a right trianglr whose hypotenuse is the line segment A(-6,4) B(2,-1)

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Given hypotenuse is the line segment A(-6,4) B(2,-1)


\text { Length of hypotenuse = } √((-6-2)^2 + (4-(-1))^2)


\text { Length of hypotenuse = } √(64 + 25)


\text { Length of hypotenuse = } \ 9.43 \text { units}

height = | 4 - (-1)|= 5 units

Base = |-6 -2| = 8 units

Perimeter = 9.43 + 5 + 8 = 22.43 units

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Answer: Perimeter = 22.43 units
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User Brian Kiremu
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