Question

What is the gravitational force fgrav on the satellite? take the gravitational constant to be g = 6.67×10−11 n⋅m2/kg2 , the mass of the earth to be me = 5.97×1024 kg , and the radius of the earth to be re = 6.38×106 m ?

Answer 1

The question is incomplete, complete question is:

A satellite used in a cellular telephone network has a mass of 2500 kg and is in a circular orbit at a height of 700 km above the surface of the earth.

What is the gravitational force on the satellite?

Take the gravitational constant to be
`G = 6.67* 10^(-11) Nm^2/kg^2` , the mass of the earth to be
`m_e = 5.97* 10^(24) kg` , and the radius of the Earth to be
`r_e = 6.38* 10^6 m`

Answer:

19,859.74 Newtons is the gravitational force on the satellite.

Step-by-step explanation:

Mass of the satellite =
`m=2500 kg`

Mass of earth =
`m_e=5.97* 10^(24) kg`

Distance between satellite and earth, d =
`r_e+700 km=6.38* 10^6 m+700,000 m=7.08* 10^6 m`

Gravitational constant =
`G= 6.67* 10^(-11) Nm^2/kg^2`

`F=G* (m* m_e)/(d^2)`

`F=6.67* 10^(-11) Nm^2/kg^2* (2500 kg* 5.97* 10^(24) kg)/((7.08* 10^6 m)^2)`

`F=19,859.74 N`

19,859.74 Newtons is the gravitational force on the satellite.

Answer 2

The gravitational force on the satellite is approximately equal to 16,757 N