Question

How many moles of bromine gas are produced

when fluorine reacts with 347.5 g of potassium
bromide?

Answer 1

23 miles of bromine gas

Answer 2

1.46 mol

Step-by-step explanation:

Given data:

Moles of bromine gas produced = ?

Mass of potassium bromide = 347.5 g

Solution:

Chemical equation:

2KBr + F₂ → 2KF + Br₂

Number of moles of KBr:

Number of moles = mass/ molar mass

Number of moles = 347.5 g/ 119.0 g/mol

Number of moles = 2.92 mol

Now we will compare the moles of KBr and bromine.

KBr : Br₂

2 : 1

2.92 : 1/2×2.92 = 1.46 mol