Question

HELP PLEASE

Find the value of x, if you know the hypotenuse is 10 and 1 of the sides is 5. X is the other side.

Answer 1

We can use Pythagorean's Theorem to solve for the unknown side:

`a^2+b^2=c^2`

Solve for b (c is the hypotenuse and it doesn't matter which side is a or b):

`b = √(c^2-a^2) = √(10^2-5^2) = √(100-25) = √(75)`

We can simplify this:

`√(75) = √(25*3) = 5 √(3)`

So, your answer is, b =
`5 √(3)`

Answer 2

Hey there! :)

For questions like these, where you are given the hypotenuse & one side of a triangle, then we can very simply use the Pythagorean Theorem to find x.

Pythagorean Theorem : a² + b² = c²

Where :

a = side length
b = another side length
c = hypotenuse

Since we are given 10 as the hypotenuse and 5 as a side length, we can very simply plug these into the Pythagorean theorem.

a² + b² = c²

We'll plug 10 into 'c' and 5 into 'a.'

(5²) + b² = (10²)

Simplify.

25 + b² = 100

Now, subtract 25 from both sides.

b² = 100 - 25

Simplify.

b² = 75

Now, find the square root of b² and 75.


`√(b^2) = √(75)`

Simplify.


`b = 5 √(3)`

Therefore, our final side length is :
`5 √(3)`

~Hope I helped!~