Question

P= $790, t= 3, r=4% compounded continuously : Find A

Answer 1

`\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount}\\\\ A=Pe^(rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to& \$790\\ r=rate\to 4\%\to (4)/(100)\to &0.04\\ t=years\to &3 \end{cases} \\\\\\ A=790e^(0.04\cdot 3)\implies A=790e^(0.12)`