Answer:
For c = 5 → two solutions
For c = -10 → no solutions
Explanation:
We know

for any real value of a.
|a| = b > 0 - two solutions: a = b or a = -b
|a| = 0 - one solution: a = 0
|a| = b < 0 - no solution
|x + 6| - 4 = c
for c = 5:
|x + 6| - 4 = 5 add 4 to both sides
|x + 6| = 9 > 0 TWO SOLUTIONS
for c = -10
|x + 6| - 4 = -10 add 4 to both sides
|x + 6| = -6 < 0 NO SOLUTIONS
Calculate the solutions for c = 5:
|x + 6| = 9 ⇔ x + 6 = 9 or x + 6 = -9 subtract 6 from both sides
x = 3 or x = -15