Question

Find the roots of the equation below 7x2+1=0

Answer 1

The roots would be 15 

Answer 2

The roots of the equation is:
`x=\pm i(√(7))/(7)`

Explanation:

Consider the provided equation.

`7x^2+1=0`

Subtract 1 from both the sides.

`7x^2+1-1=-1`

`7x^2=-1`

Isolate the variable by dividing both the side by 7.

`(7x^2)/(7)=(-1)/(7)`

`x^2=(-1)/(7)`

Take the square root:

`x=\pm \sqrt{(-1)/(7)}`

`x=\pm (1)/(√(7))i`

Now we multiply the numerator and the denominator by √7:

`x=\pm (1)/(√(7))* (√(7))/(√(7))i`

`x=\pm (√(7))/(7)i`

`x=\pm i(√(7))/(7)`

Hence, the roots of the equation is:
`x=\pm i(√(7))/(7)`