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The standard form of the equation of a circle is (x−3)^2+(y−1)^2=16.

What is the general form of the equation?

A- x^2+y^2−6x−2y−6=0

B- x^2+y^2−6x−2y−26=0

C- x^2+y^2+6x+2y+26=0

D- x^2+y^2+6x+2y−6=0

User Joe Sasson
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1 Answer

5 votes
so the answer is A.......
The standard form of the equation of a circle is (x−3)^2+(y−1)^2=16. What is the general-example-1
User MatejG
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