we know that
tan 29°=AC/CB--------> CB=AC/tan 29°
AC=110 ft
CB--------> how far the man is from the helicopter landing pad
so
CB=AC/tan 29°----------> CB=110/ tan 29°----------> CB=198.45 ft
I did it and it was correct!
the answer is
the man is 198.45 ft from the helicopter landing pad