Question

Part A (7 points): How many grams of iron (Fe) will be produced if you start with 3.65 liters of carbon monoxide gas (CO) at STP?

Part B (3 points): Jacob performed the above experiment in his chemistry class, and collected 4.23 grams of iron. What is the percent yield?

Fe2O3 + 3 CO --> 2 Fe + 3 CO2

Answer 1

what is this? i still haven't gotten this bonus question.

Answer 2

The given balanced chemical equation is,

`Fe_(2)O_(3) + 3CO -->2 Fe (s) + 3CO_(2)(g)`

Part A:

Converting 3.65 L CO to moles:

`3.65 L * (1 mol)/(22.4 L) = 0.163 mol CO`

Moles of Fe that will be produced from 0.163 mol CO:

`0.163 mol CO * (2 mol Fe)/(3 mol CO) = 0.1086 mol Fe`

Mass of Fe =
`0.1086 mol Fe * (55.85 g)/(1 mol) = 6.07 g Fe`

Part B: Actual yield of Fe = 4.23 g Fe.

Theoretical yield = 6.07 g Fe

Percentage yield =
`(Actual yield (g))/(Theoretical yield (g))*100`

=69.7 %