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Simplify complex fraction ( ( 2x - 5 ) / ( x^2 - 9) ) / ( ( 3x - 1 ) / ( x + 3 ) )
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Simplify complex fraction
( ( 2x - 5 ) / ( x^2 - 9) ) / ( ( 3x - 1 ) / ( x + 3 ) )

User Sao
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2 Answers

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( ( 2x - 5 ) / ( x^2 - 9) ) / ( ( 3x - 1 ) / ( x + 3 ) )=

=( ( 2x - 5 ) / ( x-3)(x+3) ) / ( ( 3x - 1 ) / ( x + 3 ) )=

= ( ( 2x - 5 ) / ( x-3) / ( ( 3x - 1 ) )=( 2x - 5 ) ( 3x - 1 )/( x-3)
User Riten
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1 vote
Hope this helped! Ask me if there's any part of the working you don't understand! :)
Simplify complex fraction ( ( 2x - 5 ) / ( x^2 - 9) ) / ( ( 3x - 1 ) / ( x + 3 ) )-example-1
User Christopheraue
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6.2k points
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